$h\left(x\right)=\left(\ln\left(x\right)\right)\left(3x^3\right)$
$12x^3y-18x^4y^2+30x^2y$
$r^2\:+\:2r\:+\:1$
$\:x\:+\:7\:<\:-\:3\:\left(x\:-\:1\:\right)$
$2 x - 11 = 3$
$\cos\left(x\right)\left(\frac{1}{\tan\left(x\right)}\right)$
$\left(1\right)\left(-1\right)-2^3+\sqrt[4]{16}-6$
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