$x^4-4x+3$
$4x-\frac{3}{5}>-x-6$
$x^2+3x-130$
$504-18-20$
$2xy-x$
$\sqrt{\left(-4^2+7^2\right)}$
$\left(5x^3+2x^2+6x-4\right)-\left(3x^2+x^2+4x-7\right)$
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