$8\left(4x-6\right)$
$\lim_{x\to0}\left(\frac{tan3x}{sin5}\right)$
$120-35$
$\left(4n+5\right)^3$
$3x^2-18x-15=0$
$\lim_{x\to5}\left(3x\:-7\right)$
$\frac{\left(x^{18}\cdot x^7\right)}{x^{-4}}$
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