$\frac{d}{dx}\left(8\sec\left(2x\right)\tan\left(2x\right)\right)$
$\frac{\sqrt{2\left(4+h\right)+1}-3}{h}$
$9\left(n+2\right)$
$\left(10y-5x\right)^2$
$x^3y-x-8y-12=0$
$\frac{dy}{dx}=\frac{4x^3+2x}{3y^2+1}$
$27x^2y+72xy+48y$
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