$\sqrt{-8}+\sqrt{2}$
$\int\frac{x^2+2}{\sqrt{9-x^2}}dx$
$\lim_{x\to-1}\left(\frac{x^2-3x\:+8}{x-1}\right)$
$\left(6a^2-7-3a\right)-\left(-5a^2-9a+6\right)$
$\int\left(-6xcos\left(9x\right)\right)dx$
$-16^0$
$x\:dx\:-\:y^2\:dy\:=\:0$
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