$\left(4x-9\right)\frac{2}{5}$
$y=x^2-2x^{-1}$
$8z+24$
$16a^2+4a+4$
$\int\left(1-3^x\right)^2dx$
$\frac{1+\cot\left(0\right)}{1+\tan\left(0\right)}$
$\int_{0.16}^{0.33}\left(\frac{1}{ln\left(\frac{y}{0.16}\right)}\right)dx$
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