$\int\left(x-3\right)e^{-6x}dx$
$3=7+x$
$\left(x^2+x\right)\left(x^2+x-2\right)$
$\lim_{n\to\infty}\left(\frac{1}{\ln\left(n+1\right)}\right)$
$\int\left(7x^2-6x\right)e^{4x}dx$
$\left(1+x\right)^2\left(1+x\right)^2$
$\frac{2x^{-2}}{2x^3}$
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