$19.4^2+30\sqrt{104}$
$3x^2-12x=12x$
$m^6m^{10}m^5g$
$\left(3x^2+4xy\right)^2$
$\lim_{x\to1}\left(\frac{x^{12}-1}{x^{16}-1}\right)$
$cos\left(2x\right)-cos\left(4x\right)=sqrt\left(3\right)\:sen\left(3x\right)$
$\left(-4n^2+2mn+3m^2\right)\left(2m^2+6n^2-5mn\right)$
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