$\int_0^{\frac{\pi}{2}}\left(\frac{1}{3+\cos\left(2x\right)}\right)dx$
$\int ( t + 2 ) ( t - 2 ) d t$
$5\sin x-2\cos^2x-1=0$
$0.6931471805599453+0.3620454462036935\:$
$\cos\left(x\right)=04$
$\int4^{3x}dx$
$\int_{-1}^2\left(\frac{x^2}{k}\right)dx$
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