$4^{5-1}$
$\left(10x^3-6x^2-2x-8\right)-\left(3x^3-7x^2+2x-12\right)$
$\frac{x+8}{-2}>0$
$2nm^2\cdot4m^2n^{-3}$
$4x^2-4x+5$
$-2\left(x+3\right)^2\:=\:\left(x+8\right)\:\left(x-6\right)$
$\int-3\left(cosx\right)^3sin\left(x\right)dx$
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