$\frac{1}{\sin\left(x\right)\cos\left(x\right)}=\frac{\cos\left(x\right)}{\sin\left(x\right)}+\frac{\sin\left(x\right)}{\cos\left(x\right)}$
$\left(3x-1\right)\left(3x+3\right)$
$x^2-x-20\ge0$
$x^2-8x-20=0$
$\left(3xy-4z^2\right)^2$
$4x^2+20x+24$
$5\left(x-7\right)+6x+2$
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