$\lim_{x\to\infty}\left(\frac{3^x}{2^{x^3}}\right)$
$2sin^2=sin^2$
$-\frac{3}{x^2+8x+16}$
$\:25x^2\:-\:36$
$u^2-2u-15$
$-4=48$
$-4\cdot5+-2+-48+-4-3200$
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