$6g+12=24$
$\frac{dy}{dx}=\frac{4x}{y^2}$
$\left(3x-2\right)\left(4-y\right)$
$\left(y-10\right)^2$
$\frac{x-1}{x+5}-2\ge0$
$5-\:\left(3-5\right)\:+4.\left(6-3\right)\:+27\::\:\left(-3\right)$
$4y+5=5y-6$
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