$\frac{3x^3-8x^2+6x+8}{x+4}$
$4y^4-4y=0$
$\left(3x^3-2y\right)-\left(5y-2x^3+5\right)+\left(4+7y\right)$
$\left(a^2+a^5\right)^2$
$4x-2=-4x+6$
$\frac{16.666665}{.329233889}$
$-45ab2c+15ab2c$
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