$\left(6-x\right)\left(x+3\right)$

$\lim_{x\to\infty}\left(\sqrt{x^2-4}\right)-\left(\sqrt{x^2+2}\right)$

$5.50-3.50+1.50$

$\left(\frac{x^2}{y^2}\right)x$

$f\left(x\right)=\frac{\left(x+3\right)^8}{\left(4x-16\right)^{10}}$

$\int x^6\cdot\cos\left(x\right)dx$

$x+y+6x-4y-2$