$\left(x^3+12\right)\left(x^2+12\right)\left(x+48\right)$
$\int_1^{\infty}\left(\frac{5}{2x+6}-\frac{5}{x}\right)dx$
$8^2$
$2\left(4\cos^2x-3\sin^2x\right)$
$3\:a\:m^3+6\:a^3\:m$
$2x^2-12x+18$
$\frac{\left(x-2\right)}{5}+\frac{x}{10}=\frac{1}{2}$
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