$x^2+12>7x$
$\left(6x-3\right)\left(6x+1\right)$
$-5\left(1-3m+n\right)$
$\left(1-e^3+f^4\right)^2$
$\int\left(\frac{u+1}{2u}\right)^2du$
$x+\frac{1^8}{8}$
$a^7b^3c^4:\:a^3b^2c$
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