$7x-11\le4x$
$3x-x^2+5x+2x^2-x-1$
$\frac{26}{0.37}$
$-6-1.5\left(4b+8\right)=3\left(-6-2b\right)$
$\frac{\left(\infty+1\right)}{2\infty+3}$
$x^2+2x-8=0$
$\left(3a^2+a^4\right)^2$
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