$\left(\frac{2x^3}{4y^{-1}}\right)^2$
$\lim_{x\to\infty}\left(\frac{x^2+2x+1}{x^2+3}\right)$
$\left(8-5x\right)\left(8-2y\right)$
$-7a+2b+a-b$
$8\cos x=-1$
$\cos^2x\left(\sin x\tan x\sec x+1\right)$
$\int\frac{16x+13}{4x^2+7x+12}dx$
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