$\left(9-q\right)^2\:\left(9+q^2\right)$
$\frac{x+7}{\left(x+1\right)\left(x-2\right)\:}=\frac{a}{x+1}+\frac{b}{x-2}$
$2xy+6xy-5xy$
$4x^2+1xy^2+625$
$7x^4+4x^2+7x+2-6x^3+8x+3$
$\lim_{x\to0}\left(\frac{14-14\cos\left(x\right)}{7}\right)$
$1.01^{29}$
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