$3x-4y+8a-6+-7x+3y-a-10+-x+y+5a+8$
$\left(a^2+4a\right)^2$
$\int\frac{x^2-6x}{\left(x-2\right)\left(x^2+4\right)^2}dx$
$\frac{17^{10}}{17^8}$
$\int\left(x+4\right)\sqrt{x}dx$
$x^4+x^3-24$
$1800\cdot\frac{1}{3}$
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