$3x^2-4x=7$
$\sqrt[3]{\frac{8a^5}{2}}+\sqrt[3]{\frac{a^2}{4}}$
$\left(6\cdot10^3\right)+\left(2\cdot10^2\right)$
$6a^2+7b^3-10c-5b^3+7c+5c-4^2$
$\:13x\:+\:14x\:+\:20xy$
$x^8-256$
$1024x^2+1152x+324$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!