$\left(\frac{1}{4}x^2+\frac{1}{3}y-1\right)^2$
$x\frac{dy}{dx}2y=x^4$
$6:2-2\left(3-1\right)$
$3y'=x-xy$
$\int_{-1}^112e^{-3x}dx$
$\frac{x^3-2^2+x}{x-5}$
$\left|\left(-2\right)^3\right|^2\cdot\left(2^2\right)^3$
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