$dx+e^{3y}dy=0$
$\left(-12+5i\right)^3$
$525\cdot40$
$\lim_{x\to\infty}\left(\frac{e^{5x-7}}{6x}\right)$
$-4:-12$
$z^2-64$
$\frac{x+6}{3x+2}\:-\frac{3x}{x-5}$
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