$\left(1+u\right)^5$
$4-6m^x$
$\frac{d}{dx}s^2+\frac{1}{4}i^2=si+i$
$xdx-\sqrt{a^2-x^2}dy=0$
$\frac{-\sec\left(x\right)}{1-\cos\left(x\right)}$
$\left(6x^2+3x-5\right)\left(x-2\right)$
$\frac{4}{x+2}<\frac{1}{x-1}$
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