$\frac{x}{x^2-1}+3\le\frac{1}{x-1}-\frac{x}{x+1}$
$\int x^2\cdot\left(7+2x^3\right)$
$\sqrt[5]{\frac{x}{x+1}}$
$\frac{3x^3-8x^2+6x-5}{x+2}$
$2:\left(-1\right)-3$
$49r^2-84r+36$
$6x^2-x-12>0$
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