$\frac{tan^2x\:secx}{cos2x}$
$4x^2-x-3=0$
$\frac{2x^3+6x+12}{x+2}$
$\left(7x+2y\right)\frac{dy}{dx}=-2x-7y$
$-321+28$
$m^2-2m+1=0$
$4\cdot157$
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