$\frac{2x-3}{5}-3x\ge\frac{8x+1}{6}-7x$
$\sqrt{2x^2}+2$
$\lim_{x\to0}\left(\frac{2\sin\left(8x^6\right)}{-3x}\right)$
$\left(e^2\right)\left(2\right)^2$
$\:\:\:\:+3\:-5\:+7\:$
$2x\:cos\:360\:-3x\:tg\:135\:+\:cotg\:225$
$-10.5=\log_{10}\left(x\right)$
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