$\left(3x^3-1\right)\left(3x^3+2\right)$
$\frac{\left(3-x^2+x^4\right)}{x^3}$
$9y^2-90yz+225z^2$
$\left(z^2+8\right)^3$
$x^2-2x+17=0$
$+4\:-\:\left(-6\right)$
$3y^2\left(2x^2+5xy-6y^2\right)$
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