$4\left(3\right)^2\left(2\right)^3+5\left(2\right)-3\left(3\right)$
$\int x^4\left(1+x^5\right)^8dx$
$\frac { d y } { d x } = \frac { x + 2 } { y ^ { 2 } }$
$4x-14+9x-63$
$\int-x^3\left(-x^3+6\right)^5dx$
$3\tan\theta=5\sin\theta$
$3x^2+7x+12=0$
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