$\frac{x-11}{10}=\frac{x-10}{8}$
$cos^3a=\frac{\left[cos\left(3a\right)+3cosa\right]}{4}$
$k=\cot\left(x\right)\cdot\sin\left(x\right)+\cos\left(x\right)^2\cdot\sec\left(x\right)$
$\lim_{x\to\infty}\left(\frac{9x}{9x+1}^{6x}\right)$
$\left(+2\right)\cdot\left(+3\right)\cdot\left(-6\right)$
$x^3-3x^2-24x+80$
$\left(-x^2+6x-8\right)^2$
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