$\left(-3xy\right)^2\cdot\left(-5xy\right)$
$10a^4b^2-18a^2b^3$
$\frac{4x^{-3}y^0}{4xy^4}$
$\frac{6x^3}{x^2}\cdot\frac{x^2-3x+1}{2x^2}$
$-80x+320$
$\int3\left(6+3x\right)^6dx$
$3y'\:+xy\:=\:x$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!