$\lim_{x\to0}\left(\frac{yx^2+x-1}{yx}\right)$
$m\left(x\:-\:y\right)$
$2\left(\frac{1}{8}x+y\right)$
$y^2-8=0\:$
$\left(x-9\right).5$
$\frac{-3x^3-18x^2+21x+180}{x+4}$
$-12a\left(m-n+1\right)\:+\:\left(-m+n-1\right)\:+m\:\left(6m+6n+6\right)$
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