$\lim_{x\to\infty}\left(\frac{2e^x}{x^3}\right)$

$3+4\left(x-2\right)=-3-5\left(x-5\right)$

$\frac{\cot\left(b\right)^2-1}{\cot\left(b\right)^2}$

$\left(2xy^3-y+2\right)dx+\left(3x^2y^2-x+7\right)dy=0$

$2x^2-3x-27$

$4=256$

$\int_0^{\infty}\left(\frac{e^x}{e^2+1}\right)dx$