$x+1\le5$
$w^2-1$
$\left(3a-\frac{2}{3}\right)^2$
$\lim_{x\to\infty}\left(\frac{1}{2^x}\right)$
$x-4>2x+3$
$\left(4a^2-ab+2b^2\right)\left(2a-3b\right)$
$-25x=-25$
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