$\int\frac{5x+3}{\left(x^2+x\right)}dx$

$\lim_{x\to-1}\left(\left(\frac{1}{x+1}\right)\right)$

$5+\left(-4\right)\cdot\left(7-\left(-3\right)\cdot\left(-2\right)\right)$

$\int\frac{x^8}{\left(4-x^2\right)^{\frac{11}{2}}}dx$

$\frac{\left(8m^3+27\right)}{2m+3}$

$378.2\cdot3.47$

$144\times4^4-81a^4b^2$