$\frac{d^2}{dx^2}\left(4x^2+3y^2=4\right)$
$\frac{dy}{dx}=\frac{5x^2}{4y}\:$
$y=3\cos\left(2\right)x$
$y+-5=-10$
$\lim_{x\to-1}\left(\frac{x^3-1}{x+\left|1\right|}\right)$
$\lim_{x\to\infty}\left(\frac{2x^2}{e^x}\right)$
$1+y'=e^y$
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