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# Simplify the expression $\frac{2x^2-x-1}{x}$

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##  Final answer to the problem

$\frac{\left(x-1\right)\left(2x+1\right)}{x}$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Write in simplest form
• Solve by quadratic formula (general formula)
• Find the derivative using the definition
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
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Factor the trinomial $2x^2-x-1$ of the form $ax^2+bx+c$, first, make the product of $2$ and $-1$

$\left(2\right)\left(-1\right)=-2$

Learn how to solve simplification of algebraic fractions problems step by step online.

$\left(2\right)\left(-1\right)=-2$

Learn how to solve simplification of algebraic fractions problems step by step online. Simplify the expression (2x^2-x+-1)/x. Factor the trinomial 2x^2-x-1 of the form ax^2+bx+c, first, make the product of 2 and -1. Now, find two numbers that multiplied give us -2 and add up to -1. Rewrite the original expression. Factor 2x^2-2x+x-1 by the greatest common divisor 2.

##  Final answer to the problem

$\frac{\left(x-1\right)\left(2x+1\right)}{x}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Simplification of algebraic fractions

Simplification or reduction of algebraic fractions is the action of dividing the numerator and denominator of a fraction by a common factor in order to obtain another much simpler equivalent fraction. We can say that a fraction is reduced to its simplest when there is no common factor between the numerator and the denominator.