$\frac{d}{dx}\left(\left(x^4-y^4\right)^8=ln\left(2x^3+y^5\right)\right)$

$\left(\frac{2}{5}a+\frac{3}{4}b\right)^3$

$1-12+2-14$

$2\left(\cos\left(x\right)+\cos\left(x\right)^2\right)$

$\frac{d^2}{dx^2}\left(x^{\frac{22}{7}}\right)$

$\left(17ab\right)\left(-4b^2\right)$

$\frac{dy}{dx}=\frac{y+4}{x^3}$