$\sqrt{3\cdot2}\cdot\sqrt{x}$
$\frac{d}{dx}\left(\frac{\sqrt{x+1}}{\left(x+3\right)\cdot3\sqrt[3]{x+4}}\right)$
$52^2-2-7$
$\left(-6\right)\left(-5\right)$
$2x+5-2x+1$
$\left(3^2\right)^2-\left(-4\right)^2$
$\left(-3+7\right)\left(-5-11\right)$
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