$tan\left(x\right)cos^2\left(x\right)=\frac{\left(sin\left(x\right)-sin^3\left(x\right)\right)}{cos\left(x\right)}$

$x^2\left(x^3+3\right)^4$

$\frac{m^2-1}{m-1}$

$4y+5>6y+7$

$\int\frac{4x-2}{x^3-x^2+x}dx$

$\left(\frac{2x}{5}-y\right)\left(\frac{2x}{5}+y\right)$

$2-y=9$