$\int_0^{\frac{1}{2}}\left(\frac{1}{\left(1+4x^2\right)}\right)dx$

$\frac{d}{dz}\left(z+1=-2y+\sqrt{z^2-x}\right)$

$\left(-6+3\cdot\left(4-\frac{35}{5}\right)\right)-\left(5-3\cdot\left(13-11\right)\right)$

$9x-4=7-2x$

$\int\frac{x}{\sqrt{r^2-x^2}}dx$

$103\left(x-3\right)^2$

$9ax+81b$