$\left(1\right)ydx-\left(4\right)y=\left(3\right)e^{\left(1\right)x}y^4$
$\frac{du}{dx}=\cos\left(u\right)$
$\sqrt{x^2+8x+16}$
$2\left(7-9-8+5\right)^2-3\sqrt[3]{8}$
$\frac{dy}{dx}=\frac{3y}{100-x}$
$3\left(5x-2\right)=39$
$2x+3y-12=0$
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