$\left(-\frac{3}{4}y-\frac{5}{4}\right)^2$
$\left(m-8\right)\:\left(m+8\right)$
$\frac{x^5-x^3+x}{x-2}$
$\frac{64m^6-125n^9}{4m^2-5n^3}$
$4^{x+3}=\left(\frac{1}{2}\right)^x$
$6y-4+2y$
$2-3\cdot5+9-2\cdot4$
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