$9x^2-31x-20$
$-n+4-9-5n$
$\sin^2\cdot\sec^2\cot^2=1$
$-3x^2+6x-2$
$\frac{4n^2}{2n^{.5}}$
$\frac{\tan\left(x\right)-\sec\left(x\right)}{\sin\left(x\right)-1}=\sec\left(x\right)$
$\left(-12\right)-\left(6-1\right)-\left(-4\right)$
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