$\ln\left(6t+5\right)=-5$
$\frac{du}{dt}=e^{2u+3t};\:u\left(0\right)=3$
$\lim_{x\to0}\left(\frac{4-x}{x+\sqrt[3]{1-x^3}}\right)$
$\left(13-12\right)-\left(5-7\right)$
$\sqrt[2]{zx^3}$
$\frac{\cos\left(x\right)}{-2\sin\left(2x\right)}$
$-3-\left(5+11\right)$
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