$\frac{1}{2}\left(b+c\right)d$

$24a^2b^2-8ab^2$

$\int\left(\frac{1}{\tan\left(x\right)^4}\right)dx$

$x+2=a\left(x-5\right)+b\left(x+3\right)$

$\left[\frac{7^2\cdot\:\left(11^3\right)^4\cdot\:\left(7^3\right)^3\cdot\:11^3}{11^8\cdot\:\left(7^2\right)^5\cdot\:11^6}\right]^3$

$\left(x+2\right)\left(5x-2\right)$

$\left(-1\right)^{n-1}\cdot\frac{2^n}{5^n}$