$\cos^2a+\cos^2b=1$
$4y''-4y'-15y=0$
$dy=4xdx$
$\frac{1}{2}\left(2x+3\right)<6$
$\lim_{x\to2}\left(sin^2\left(\pi x\right)\sin\left(\frac{1}{x^2-4}\right)\right)$
$\int10\arcsin\left(6x\right)dx$
$x^2-6x+16=0$
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