Simplifying
$\left(\frac{2x^2-3x-1}{x+3}\right)$
$6-5\cdot\left(-7\right)$
$\left(x^2+xy+y^2\right)\cdot4x-\left(x^4-y^4\right)\cdot\left(\:2x+y\right)$
$\left(3a+4b-6c+9d^3-2\right)\left(3a+4c-6c+9d^3-2\right)$
$243\cdot3$
$\cot\left(x\right)=\frac{\sqrt{3}}{3}$
$3e^{1.4}$
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