$x^2-4x>-3$
$1.08+6.92$
$\int\frac{9}{7}y^{4}dy$
$\lim_{x\to\infty}\:2^{x+1}$
$\int\frac{10x-6}{\left(x^2-4\right)\left(x^2-2x+1\right)}dx$
$-4\:+\:15\::\:3$
$\left(3uv^6\right)^2$
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